Engineering math formula for GATE/BARC/ISRO

Engineering MathematicsΒ is one of the scoring sections inΒ GATE/BARC/ISRO Exam. Looking at your requirement, we are sharing with you Important Engineering Mathematics Formulas & Shortcuts for Competitive Exam as well as Engineering exam.

  1. IfΒ π‘Ÿβ‰ π‘Ÿβ€², no solution, ifΒ π‘Ÿ=π‘Ÿβ€²=𝑛, unique solution ifΒ π‘Ÿ=π‘Ÿβ€²<𝑛, many solutions. (non-homogeneous)
  2. IfΒ π‘Ÿ=𝑛, trivial solution, ifΒ π‘Ÿ<𝑛 ,then (π‘›βˆ’π‘Ÿ) linearly independent solutions. (Many solutions) and ifΒ π‘š<𝑛, then many solutions.
  3. 𝑓(π‘₯+β„Ž) =𝑓(π‘₯) +β„Žπ‘“β€²(π‘₯) +β„Ž22!𝑓′′(π‘₯) +β„Ž33!𝑓′′′(π‘₯) + β€¦β€¦β€¦βˆž
  4. IfΒ π‘Ÿπ‘‘βˆ’π‘ 2>0 andΒ π‘Ÿ<0 𝑓(π‘₯,𝑦) have maximum, ifΒ π‘Ÿπ‘‘βˆ’π‘ 2>0 andΒ π‘Ÿ>0 𝑓(π‘₯,𝑦) have minimum at(π‘Ž,𝑏) and ifΒ π‘Ÿπ‘‘βˆ’π‘ 2<0, then saddle point. IfΒ π‘Ÿπ‘‘βˆ’π‘ 2=0,π‘“π‘’π‘Ÿπ‘‘β„Žπ‘’π‘ŸΒ investigation is required to decide.
  5. βˆ«π‘(βˆ…π‘‘π‘₯+πœ“π‘‘π‘¦)=∫∫𝐸(πœ•πœ“πœ•π‘₯βˆ’πœ•βˆ…πœ•π‘¦)𝑑π‘₯𝑑𝑦 (Green’s)
  6. βˆ«π‘π‘­.𝑑ℝ=βˆ«π‘†π‘π‘’π‘Ÿπ‘™π‘­.𝑁𝑑𝑠 (Stokes)
  7. βˆ«π‘†π‘­.𝑁𝑑𝑠=βˆ«πΈπ‘‘π‘–π‘£π‘­π‘‘π‘£Β (Gauss)
  8. π‘¦π‘’βˆ«π‘ƒπ‘‘π‘₯=βˆ«π‘„π‘’βˆ«π‘ƒπ‘‘π‘₯𝑑π‘₯+𝑐
  9. If 𝑀 𝑑π‘₯+𝑁 𝑑𝑦=0 be a homogeneous equation inΒ π‘₯Β and 𝑦, then 1𝑀 π‘₯+𝑁 𝑦 𝑖𝑠 an integrating factor
  10. If the equation of the type 𝑓1(π‘₯𝑦)𝑦 𝑑π‘₯+𝑓2(π‘₯𝑦)π‘₯ 𝑑𝑦=0. If the equation 𝑀 𝑑π‘₯+𝑁 𝑑𝑦=0 be of this type then 1𝑀 π‘₯βˆ’π‘Β π‘¦Β is an integrating factor
  11. IfΒ πœ•π‘€πœ•π‘¦βˆ’πœ•π‘πœ•π‘₯𝑁 be a function of x only = 𝑓(π‘₯) say thenΒ π‘’βˆ«π‘“(π‘₯)𝑑π‘₯Β is an integrating factor

 

  1. IfΒ πœ•π‘πœ•π‘₯βˆ’πœ•π‘€πœ•π‘¦π‘€Β be a function of y only = 𝑓(𝑦) say thenΒ π‘’βˆ«π‘“(𝑦)𝑑𝑦 is an integrating factor.
  2. βˆ«π‘€π‘‘π‘₯𝑦=π‘π‘œπ‘›π‘‘Β +∫terms of N not containing x dy=c
  3. 𝑃.𝐼.=1𝑓(𝐷)π‘’π‘Žπ‘₯=1𝑓(π‘Ž)π‘’π‘Žπ‘₯Β , 𝑓(π‘Ž)β‰ 0, if 𝑓(π‘Ž)=0,π‘‘β„Žπ‘’π‘›Β π‘ƒ.𝐼.=π‘₯1𝑓′(π‘Ž)π‘’π‘Žπ‘₯,𝑓′(π‘Ž)β‰ 0
  4. 𝑃.𝐼=1𝑓(𝐷2)sin(π‘Žπ‘₯+𝑏)= 1𝑓(βˆ’π‘Ž2), 𝑓(βˆ’π‘Ž2)β‰ 0, if 𝑓(βˆ’π‘Ž2)=0,

then 𝑃.𝐼. =π‘₯1𝑓′(βˆ’π‘Ž2)sin(π‘Žπ‘₯+𝑏), 𝑓′(βˆ’π‘Ž2)β‰ 0

  1. 𝑃.𝐼.=1𝑓(𝐷)π‘’π‘Žπ‘₯𝑉=Β π‘’π‘Žπ‘₯1𝑓(𝐷+π‘Ž)𝑉
  2. 𝑃.𝐼=1𝑓(𝐷)π‘₯π‘š=[𝑓(𝐷)]βˆ’1π‘₯π‘š,
  3. (1+π‘₯)βˆ’1=1βˆ’π‘₯+π‘₯2βˆ’β‹―
  4. (1βˆ’π‘₯)βˆ’1=1+π‘₯+π‘₯2+β‹―
  5. π‘₯𝑛𝑑𝑛𝑦𝑑π‘₯𝑛+π‘˜1π‘₯π‘›βˆ’1π‘‘π‘›βˆ’1𝑦𝑑π‘₯π‘›βˆ’1+β‹―π‘˜π‘›βˆ’1π‘₯𝑑𝑦𝑑π‘₯+π‘˜π‘›π‘¦=𝑋,Β π‘₯=𝑒𝑑 ,Β π‘₯𝑑𝑦𝑑π‘₯=𝐷𝑦,Β π‘₯2𝑑2𝑦𝑑π‘₯2=𝐷(π·βˆ’1)𝑦,Β π‘₯3𝑑3𝑦𝑑π‘₯3=D(Dβˆ’1)(Dβˆ’2)
  6. πœ•πœ•π‘₯(βˆ«β„Ž(𝑑,π‘₯)𝑑𝑑𝑔(π‘₯)𝑓(π‘₯))=βˆ«πœ•πœ•π‘₯β„Ž(𝑑,π‘₯)𝑑𝑑𝑔(π‘₯)𝑓(π‘₯)+𝑑𝑔𝑑π‘₯Β β„Ž[𝑔(π‘₯),π‘₯]βˆ’π‘‘π‘“π‘‘π‘₯Β β„Ž[𝑓(π‘₯),π‘₯]
  7. 𝐿{𝑓(𝑑)}=βˆ«π‘’βˆ’π‘ π‘‘βˆž0 𝑓(𝑑)𝑑𝑑
  8. 𝐿(1)=1𝑠
  9. 𝐿(𝑑𝑛)=𝑛!𝑠𝑛+1
  10. 𝐿(π‘’π‘Žπ‘‘)=1π‘ βˆ’π‘Ž
  11. 𝐿(sinπ‘Žπ‘‘)=π‘Žπ‘ 2+π‘Ž2
  12. 𝐿(cosπ‘Žπ‘‘)=𝑠𝑠2+π‘Ž2
  13. 𝐿(sinhπ‘Žπ‘‘)=π‘Žπ‘ 2βˆ’π‘Ž2
  14. 𝐿(coshπ‘Žπ‘‘)=𝑠𝑠2βˆ’π‘Ž2
  15. 𝐿{π‘’π‘Žπ‘‘π‘“(𝑑)}= 𝑓̅(π‘ βˆ’π‘Ž)
  16. 𝑓(𝑑+𝑇)=𝑓(𝑑) then 𝐿{𝑓(𝑑)}= βˆ«π‘’βˆ’π‘ π‘‘Β π‘“(𝑑)𝑑𝑑𝑇01βˆ’π‘’βˆ’π‘ π‘‡
  17. 𝐿{𝑓′(𝑑)}=𝑠𝑓̅(𝑠)βˆ’π‘“(0)
  18. 𝐿{𝑓𝑛(𝑑)}= 𝑠𝑛𝑓̅(𝑠)βˆ’π‘ π‘›βˆ’1𝑓(0)βˆ’π‘ π‘›βˆ’2𝑓′(0)βˆ’β‹―β€¦β€¦..π‘“π‘›βˆ’1(0)
  19. 𝐿{βˆ«π‘“(π‘₯)𝑑π‘₯𝑑0}= 1𝑆𝑓̅(𝑠)
  20. 𝐿{𝑑𝑛𝑓(𝑑)}=(βˆ’1)𝑛𝑑𝑛𝑑𝑠𝑛.[𝑓̅(s)]
  21. 𝐿{1𝑑𝑓(𝑑)}= βˆ«π‘“Μ…(s) βˆžπ‘†π‘‘π‘ 
  22. 𝑓(π‘₯)=π‘Ž02+ Ξ£π‘Žπ‘›βˆžπ‘›=1cos𝑛π‘₯+ Ξ£π‘π‘›βˆžπ‘›=1sin𝑛π‘₯
  23. π‘Ž0=1πœ‹βˆ«π‘“(π‘₯)𝑑π‘₯𝛼+2πœ‹π›Ό,Β π‘Žπ‘›=1πœ‹βˆ«π‘“(π‘₯) cos𝑛π‘₯𝑑π‘₯𝛼+2πœ‹π›Ό, 𝑏𝑛=1πœ‹βˆ«π‘“(π‘₯) sin𝑛π‘₯𝑑π‘₯𝛼+2πœ‹π›Ό
  24. 𝑓(π‘₯)=π‘Ž02+ Ξ£π‘Žπ‘›βˆžπ‘›=1cosπ‘›πœ‹π‘₯𝑐+ Ξ£π‘π‘›βˆžπ‘›=1sinπ‘›πœ‹π‘₯𝑐
  25. 40.Β π‘Ž0=1π‘βˆ«π‘“(π‘₯)𝑑π‘₯𝛼+2𝑐𝛼,Β π‘Žπ‘›=1π‘βˆ«π‘“(π‘₯) cosπ‘›πœ‹π‘₯𝑐𝑑π‘₯𝛼+2𝑐𝛼, 𝑏𝑛=1π‘βˆ«π‘“(π‘₯) sinπ‘›πœ‹π‘₯𝑐𝑑π‘₯𝛼+2𝑐𝛼
  26. 𝑓(π‘₯)= Ξ£π‘π‘›βˆžπ‘›=1sinπ‘›πœ‹π‘₯𝑐 , where 𝑏𝑛=2π‘βˆ«π‘“(π‘₯) sinπ‘›πœ‹π‘₯𝑐𝑑π‘₯𝑐0
  27. 𝑓(π‘₯)=Β π‘Ž02+ Ξ£π‘Žπ‘›βˆžπ‘›=1cosπ‘›πœ‹π‘₯𝑐 where,Β π‘Ž0=2π‘βˆ«π‘“(π‘₯)𝑑π‘₯𝑐0,Β π‘Žπ‘›=2π‘βˆ«π‘“(π‘₯) cosπ‘›πœ‹π‘₯𝑐𝑑π‘₯𝑐0
  28. πœ‡=Σ π‘₯𝑗𝑓(π‘₯𝑗)π‘—Β π‘Žπ‘›π‘‘Β πœ‡=∫π‘₯ 𝑓(π‘₯)𝑑π‘₯Β βˆžβˆ’βˆž
  29. 𝜎2=Ξ£ (π‘₯π‘—βˆ’πœ‡)2𝑓(π‘₯𝑗)Β π‘—π‘Žπ‘›π‘‘Β πœŽ2=∫(π‘₯βˆ’πœ‡)2 𝑓(π‘₯)𝑑π‘₯βˆžβˆ’βˆž
  30. π‘€π‘’π‘Žπ‘›:𝑛𝑝=πœ‡Β π‘‰π‘Žπ‘Ÿπ‘–π‘Žπ‘›π‘π‘’: 𝜎2=πœ‡Β (Poisson’s distribution)
  31. 𝑓(π‘₯)=1𝜎√2πœ‹π‘’βˆ’ 12(π‘₯βˆ’πœ‡πœŽ)2 (Normal distribution)
  32. 𝑦=π‘Ž+𝑏π‘₯, Σ𝑦=π‘›π‘Ž+𝑏Σπ‘₯, Ξ£π‘₯𝑦=π‘ŽΞ£π‘₯+𝑏Σπ‘₯2
  33. 𝑦=π‘Ž+𝑏π‘₯+𝑐π‘₯2, Σ𝑦=π‘›π‘Ž+𝑏.Ξ£π‘₯+𝑐.Ξ£π‘₯2, Ξ£π‘₯𝑦=π‘ŽΞ£π‘₯+𝑏.Ξ£π‘₯2+𝑐 Σπ‘₯3, Ξ£π‘₯2𝑦=π‘ŽΞ£π‘₯2+𝑏.Ξ£π‘₯3+𝑐 Σπ‘₯4
  34. 𝑦=𝑓(π‘₯)=(π‘₯βˆ’π‘₯1)(π‘₯βˆ’π‘₯2)…(π‘₯βˆ’π‘₯𝑛)(π‘₯0βˆ’π‘₯1)(π‘₯0βˆ’π‘₯2)…(π‘₯0βˆ’π‘₯𝑛)𝑦0+(π‘₯βˆ’π‘₯0)(π‘₯βˆ’π‘₯2)…(π‘₯βˆ’π‘₯𝑛)(π‘₯1βˆ’π‘₯0)(π‘₯1βˆ’π‘₯2)…(π‘₯1βˆ’π‘₯𝑛)𝑦1+β‹―+(π‘₯βˆ’π‘₯1)(π‘₯βˆ’π‘₯2)…(π‘₯βˆ’π‘₯π‘›βˆ’1)(π‘₯π‘›βˆ’π‘₯0)(π‘₯π‘›βˆ’π‘₯1)…(π‘₯π‘›βˆ’π‘₯π‘›βˆ’1)𝑦𝑛
  35. (𝑑𝑦𝑑π‘₯)π‘₯0=1β„Ž[Δ𝑦0βˆ’12Ξ”2𝑦0+13Ξ”3𝑦0βˆ’14Ξ”4𝑦0+β‹―]
  36. (𝑑𝑦𝑑π‘₯)π‘₯𝑛=1β„Ž[βˆ‡π‘¦π‘›+12βˆ‡2𝑦𝑛+13βˆ‡3𝑦𝑛+14βˆ‡4𝑦𝑛+β‹―]
  37. π‘₯𝑛+1=π‘₯π‘›βˆ’π‘“(π‘₯𝑛)𝑓′(π‘₯𝑛) (Newton-Raphson)
  38. βˆ«π‘“(π‘₯)𝑑π‘₯π‘₯0+π‘›β„Žπ‘₯0=β„Ž2[𝑦0+𝑦𝑛+2(𝑦1+𝑦2+β‹―..+π‘¦π‘›βˆ’1)] (Trapezoidal)
  39. βˆ«π‘“(π‘₯)𝑑π‘₯π‘₯0+π‘›β„Žπ‘₯0=β„Ž3[(𝑦0+𝑦𝑛)+4(𝑦1+𝑦3+β‹―π‘¦π‘›βˆ’1)+2(𝑦2+𝑦4+β‹―π‘¦π‘›βˆ’2)] (Simpson’s)
  40. πΈπ‘Ÿπ‘Ÿπ‘œπ‘Ÿ=βˆ’π‘βˆ’π‘Ž12β„Ž2 𝑓′′(πœ‰)=𝑂(β„Ž2) (Trapezoidal)
  41. πΈπ‘Ÿπ‘Ÿπ‘œπ‘Ÿ=βˆ’π‘βˆ’π‘Ž180β„Ž4𝑓𝑖𝑣(πœ‰)=𝑂(β„Ž4) (Simpson’s)
  42. π‘¦π‘˜+1=π‘¦π‘˜+β„Ž.𝑓(π‘‘π‘˜,π‘¦π‘˜) where 𝑑𝑦𝑑π‘₯=𝑓(𝑑,𝑦) (Euler’s)

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